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A chemist has two large containers of sulfuric acid solution...?
A chemist has two large containers of sulfuric acid solution, with different concentrations of acid in each container. Blending 300 mL of the first solution and 600 mL of the second gives a mixture that is 45% acid, whereas 100 mL of the first mixed with 500 mL of the second gives 41.5% acid mixture. What are the concentrations of sulfuric acid in the original containers?
to help u understand it, let me give example: if u have a 100mL with 20% concentrationand u add it to another 200mL with 30% concentration, u'll have: total volume= 100+200 = 300mL to find the final concentration, u need to understand that it is relevant to the volume, i.e 0.2*100 + 0.3*200 = C*300 C = 26.6% so, in maths speeking: x: concentration of container a y: concentration of container b c: concentration of mixture Va: the volume used from container a Vb: the volume used from container b V: Total volume (Va + Vb) xVa + yVb = cV so 300x + 600y = 0.45*(300+600) 300x + 600y = 405 .........eq1 and 100x + 500y = 0.415 (100+500) 100x + 500y = 249 .....eq2 solve eq1 & eq2 300 x + 600y = 405 ...............eq1 (100x + 500y = 249) * -3 ...........eq2 -300x - 1500y = -747 add -900y = -342 y = 0.38 substitute in eq1 300 x + 600 (0.38) = 405 x= 0.59 so x = 59% y = 38%
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12th grade math problem: Finding concentrations of acid?
A chemist has two large containers of sulfuric acid solution, with different concentrations of acid in each container. Blending 300 mL of the first solution and 600 mL of the second gives a mixture that is 45% acid, whereas 100 mL of the first mixed with 500 mL of the second gives 41.5% acid mixture. What are the concentrations of sulfuric acid in the original containers?
x: concentration of container a y: concentration of container b c: concentration of mixture Va: the volume used from container a Vb: the volume used from container b V: Total volume (Va + Vb) xVa + yVb = cV so 300x + 600y = 0.45*(300+600) 300x + 600y = 405 .........eq1 and 100x + 500y = 0.415 (100+500) 100x + 500y = 249 .....eq2 solve eq1 & eq2 300 x + 600y = 405 ...............eq1 (100x + 500y = 249) * -3 ...........eq2 -300x - 1500y = -747 add -900y = -342 y = 0.38 substitute in eq1 300 x + 600 (0.38) = 405 x= 0.59 so x = 59% y = 38%
Math problem dealing acid solutions!?
A chemist has two large containers hydrochloric acid (HCl) solution. The concentrations of the acid is different in the two containers. She blends 90 mL of the first solution with 10 mL of the second solution to obtain a solution that is 16.05.% acid. She blends 50 mL of the first solution with 200 mL of the second solution to obtain a solution that is 12.90.% acid. What are the concentrations of hydrochloric acid in the original containers?
90x + 10y = 16.05 50x + 200y = 32.25 1800x + 200y = 321 -50x - 200y = -32.25 1750x = 288.75 x = 0.165 = 16.5% 14.85 + 10y = 16.05 10y = 1.2 y = 0.12 = 12% The concentrations of the two solutions are 16.5% and 12%.
Hard Math problem Really NEED HELP!?
A chemist has two large containers of (HCL) acid solution. The concentrations of the acid is different in the two containers. She blends 30ml of the first solution with 70ml of the second solution to obtain a solution that is 14.85% acid. She blends 150ml of the first solution with 100ml of the second solution to obtain a solution that is 14.70% acid.
What are:
% HCL solution in the first solution?
% HCL solution in the second solution?
